SOLUTION: u+1/1+1/u
________
1/u+1
Okay, it sounds likee, u plus 1 over 1 plus 1 over u. alll of that over (divided by) , 1 over u+1
I can't figure out how to do it.
Thank youuu
Algebra.Com
Question 175668This question is from textbook Algebra and Trigonometry
: u+1/1+1/u
________
1/u+1
Okay, it sounds likee, u plus 1 over 1 plus 1 over u. alll of that over (divided by) , 1 over u+1
I can't figure out how to do it.
Thank youuu.
This question is from textbook Algebra and Trigonometry
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Start by inverting the denominator fraction ( ) and multiplying times the numerator fraction.
Now your denominator has addition of an integer to a fraction. The LCD is , so . Replace the denominator with this new expression:
Again, invert and multiply:
Remove like terms from numerator and denominator:
or if you prefer.
Check the answer: You can't absolutely prove the answer this way, but you can get a pretty good idea of whether you did the manipulations correctly. Pick a number. Best is a small whole number other than zero or one. Let's try 2. If u is 2, then plugging 2 into the original expression should yield 2 X (2 + 1) = 6.
. You get to do the arithmetic to see if my solution is correct.
RELATED QUESTIONS
u+5/u-7 + 1=... (answered by jsmallt9)
20/u =... (answered by jim_thompson5910)
u+7/u-2 + 1 =... (answered by ikleyn,ankor@dixie-net.com)
How do u solve 1+3I over... (answered by ReadingBoosters)
(u+5)/(u+4)=[(u+4)/(u+6)]+1
How do I solve for... (answered by Tatiana_Stebko)
Solve for u
1 divided by u - 5 =... (answered by oberobic)
1/t=1/u+1/y
(answered by solver91311)
1/u-5/v= (answered by Fombitz)
PROVE:
1+tan(U)/1-tan(U)=... (answered by lwsshak3)