SOLUTION: use the discriminant to determine the number of real solutions of the equation: 3x^2+x-8=0

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Question 174740: use the discriminant to determine the number of real solutions of the equation: 3x^2+x-8=0
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
use the discriminant to determine the number of real solutions of the equation: 3x^2+x-8=0
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D = b^2 - 4ac
D = 1 + 96 = 97
So there are 2 real solutions.
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=97 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 1.47480963363268, -1.80814296696602. Here's your graph:
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