SOLUTION: simplify (3+3i)/(5+2i)

Algebra.Com
Question 172069: simplify
(3+3i)/(5+2i)

Found 2 solutions by Alan3354, stanbon:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
simplify
(3+3i)/(5+2i)
-----------------
These are always done by multiplying the NUM and DEN by the conjugate of the DEN. The DEN here is 5+2i, so the conjugate is 5-2i.
(3+3i)/(5+2i)
=[(3+3i)*(5-2i)]/[(5+2i)*(5-2i)]
= (15-6i+15i+6)/(25+4)
= (21 + 9i)/29



Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
simplify
(3+3i)/(5+2i)
------------------
Use FOIL:
F: 3*5 = 15
O: 3*2i = 6i
I: 5*3i = 15i
L: 3i*2i = -6
-----------------
Combine these to get: 9 + 21i
==================================
Cheers,
Stan H.

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