SOLUTION: I need some help with this problem. i asked my friend to help me with a previous problem and he ended up just giving me the answer cause i still don't get it. The one already ans

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Question 170747: I need some help with this problem.
i asked my friend to help me with a previous problem and he ended up just giving me the answer cause i still don't get it.
The one already answered ==
"":How i tried to work it out.
[]:my answer
1.
"2(x+6)(x-1)"
[x=6,(-1)]
Was that correct?
2.
?????
Please help me.

Found 2 solutions by Mathtut, MathTherapy:
Answer by Mathtut(3670) (Show Source):
You can put this solution on YOUR website!
It is not real clear what you are asking but I have a feeling you were given a solution set of x =6 and -1 and were asked to form a quadratic equation from this solution set...So we must work backward remember a quadratic equation takes the form of and when factored each factor is set to zero and the solution is found. In this case we are working backward
so....x=6...in order to make x term = to zero we must subtract 6 so x-6=0....now for x=-1 we must add 1......and get x+1=0 now these two terms can be multiplied together and set equal to zero
:
(x-6)(x+1)=0--->now multiply this out using foil
:
combine like terms
:
is our quadratic equation
If this doesnt answer your question you will have to re write your question and make it more clear....
:

Answer by MathTherapy(10704) (Show Source):
You can put this solution on YOUR website!

I need some help with this problem. i asked my friend to help me with a previous problem and he ended up just giving me the answer cause i still don't get it. The one already answered == "":How i tried to work it out. []:my answer 1. "2(x+6)(x-1)" [x=6,(-1)] Was that correct? 2. ????? Please help me. =============== For 1. , your factorization to get: "2(x+6)(x-1)" is WRONG!! Your solutions: [x=6,(-1)] are also WRONG! FOILing 2(x + 6)(x - 1), we get: = , which doesn't correspond to the given trinomial, The person who responded also has a different factorized form [(x-6)(x+1)=0--], but unfortunately, this is also WRONG! FOILing (x - 6)(x + 1) = , which doesn't correspond with the reduced trinomial, (see below). His/her solutions, x = 6, and x = - 1 are obviously WRONG too! The correct factorization and solutions follow! (x - 3)(x - 2) = 0 <==== Correct factorized form x - 3 = 0 OR x - 2 = 0 x = 3 OR x = 2 <===== CORRECT solutions ============================ Problem 2. CANNOT be factorized using integers. So, to get its roots/solutions, you'll need to use the QUADRATIC EQUATION formula