SOLUTION: I need some help with this problem. i asked my friend to help me with a previous problem and he ended up just giving me the answer cause i still don't get it. The one already ans

Question 170747: I need some help with this problem.
i asked my friend to help me with a previous problem and he ended up just giving me the answer cause i still don't get it.
The one already answered ==
"":How i tried to work it out.
[]:my answer
1.
"2(x+6)(x-1)"
[x=6,(-1)]
Was that correct?
2.
?????
Please help me.

Answer by Mathtut(3670) (Show Source): You can put this solution on YOUR website!
It is not real clear what you are asking but I have a feeling you were given a solution set of x =6 and -1 and were asked to form a quadratic equation from this solution set...So we must work backward remember a quadratic equation takes the form of and when factored each factor is set to zero and the solution is found. In this case we are working backward
so....x=6...in order to make x term = to zero we must subtract 6 so x-6=0....now for x=-1 we must add 1......and get x+1=0 now these two terms can be multiplied together and set equal to zero
:
(x-6)(x+1)=0--->now multiply this out using foil
:
combine like terms
:
is our quadratic equation
If this doesnt answer your question you will have to re write your question and make it more clear....
:

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