SOLUTION: please help me i dont understand any of this i am supposed to take algebra 2 next year this is is my problem {{{x^2-16x+56=0}}} i need this in vertex form with the work and step

Question 168915: please help me i dont understand any of this i am supposed to take algebra 2 next year this is is my problem
i need this in vertex form with the work and steps so i can understand it thank you
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
vertex form is y=a(x-h)^2+k, where (h,k) is the vertex

y=x^2-16x+56 __ subtracting 56 __ y-56=x^2-16x

completing the square by adding half of the x coefficient, squared __ y-56+(-16/2)^2=x^2-16x+(-16/2)^2

y-56+64=x^2-16x+64 __ y+8=(x-8)^2 __ subtracting 8 __ y=(x-8)^2-8

the vertex is (8,-8)
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