SOLUTION: 13i\5+i i am very confused please help

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Question 167179This question is from textbook beginning and intermediate algebra
: 13i\5+i i am very confused please help This question is from textbook beginning and intermediate algebra

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
They probably want you to get rid of "i" in the denominator
Multiply by the conjugate of (5+i) which is (5-i) over itself, (same as mult by 1)
%28%2813i%29%29%2F%28%285%2Bi%29%29 * %28%285-i%29%29%2F%28%285-i%29%29
:
Multiply the numerators and FOIL the denominators. Remember i^2 = -1
%28%2813i%29%2A%285-i%29%29%2F%28%2825+-+5i+%2B+5i+-+%28i%5E2%29%29%29 = %28%2865i+-+13i%5E2%29%29%2F%28%2825+-+%28-1%29%29%29 = %28%2865i+-+13%28-1%29%29%29%2F%28%2825+%2B+1%29%29 = %28%2865i+%2B+13%29%29%2F%2826%29 = %2865i%29%2F26 + 13%2F26
:
Note that we can reduce both fractions, they both are multiples of 13
%285i%29%2F2 + 1%2F2 = %28%281+%2B+5i%29%29%2F2 is the form they want probably
;
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