SOLUTION: (1+i)^6
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Question 164272
:
(1+i)^6
Answer by
watchmath(2)
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i+1 =sqrt(2) [cos(pi/4) + isin(pi/4) ]
Now
(i+1)^6= (sqrt(2) )^6 [cos(pi/4) +isin(pi/4)]^6
By De Moivre's
(i+1)^6= 8 {cos (8pi/4) +isin(8pi/4) )
= 8*1
=8.