How would I write the complex # y= -2+2i in trig form?
To draw the complex number , plot the point
(x,y) and connect it to the origin (,).
So to draw the complex number , we have
and
Now we plot the point (,) and connect it to
the origin (,).
now we draw a perpendicular down to the x-axis:
We label and
Now we calculate r by the Pythagorean equation:
So we label as
Next we indicate the angle @ by a curved line:
Now we determine the angle @ by any trig function
sin(@) = , cos(@) = or tan(@) =
If we use the last one we have
tan(@) =
and since we know that 45° has tangent 1, we know
the reference angle is 45°, and since @ is in the
second quadrant, the actual angle is 180°-45°or 135°.
The trig form is
r[cos(@) + i·sin(@)]
so we substitute and get:
[cos(135°) + i·sin(135°)]
and sometimes this is abbreviated as
cis(135°)
Edwin