Question 149761: Please can someone help me with this problem: For i= -1, 3i(2+5i)= x+6i,then x=?
This is how i tried to solve the problem: 3ix2=6i,and 3ix5i=15i,now i combine 6i+ 15i = x + 6i, I broke down the problem by adding 6i + 15i= 21i=x+6i, then i made the 21i negative on both sides:
21i = x + 6i
-21i -21i= -15, is this correct?
: Please can someone help me with this problem: For i= -1, 3i(2+5i)= x+6i,then x=?
This is how i tried to solve the problem: 3ix2=6i,and 3ix5i=15i,now i combine 6i+ 15i = x + 6i, I broke down the problem by adding 6i + 15i= 21i=x+6i, then i made the 21i negative on both sides:
21i = x + 6i
-21i -21i= -15, is this correct?
Answer by ankor@dixie-net.com(4535)  (Show Source):
You can put this solution on YOUR website!3i(2+5i)= x+6i,then x=?
;
Not quite: 3i * 5i = 15i^2; we know i^2 = -1. so we have:
6i + 15i^2 = x + 6i
:
6i + 15(-1) = x + 6i
which is:
6i - 15 = x + 6i
:
6i - 6i - 15 = x
:
x = -15
:
Actually much simpler than you made it to be:
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Question 149761: Please can someone help me with this problem: For i= -1, 3i(2+5i)= x+6i,then x=?
This is how i tried to solve the problem: 3ix2=6i,and 3ix5i=15i,now i combine 6i+ 15i = x + 6i, I broke down the problem by adding 6i + 15i= 21i=x+6i, then i made the 21i negative on both sides:
21i = x + 6i
-21i -21i= -15, is this correct?
: Please can someone help me with this problem: For i= -1, 3i(2+5i)= x+6i,then x=?
This is how i tried to solve the problem: 3ix2=6i,and 3ix5i=15i,now i combine 6i+ 15i = x + 6i, I broke down the problem by adding 6i + 15i= 21i=x+6i, then i made the 21i negative on both sides:
21i = x + 6i
-21i -21i= -15, is this correct?
Answer by kmcruz09(38) (Show Source):
You can put this solution on YOUR website!I didn't get the way you tried to solve the problem. But anyway, here's how the solution goes.
Distribute 3i
Take note that 
That's it.
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Question 149761: Please can someone help me with this problem: For i= -1, 3i(2+5i)= x+6i,then x=?
This is how i tried to solve the problem: 3ix2=6i,and 3ix5i=15i,now i combine 6i+ 15i = x + 6i, I broke down the problem by adding 6i + 15i= 21i=x+6i, then i made the 21i negative on both sides:
21i = x + 6i
-21i -21i= -15, is this correct?
: Please can someone help me with this problem: For i= -1, 3i(2+5i)= x+6i,then x=?
This is how i tried to solve the problem: 3ix2=6i,and 3ix5i=15i,now i combine 6i+ 15i = x + 6i, I broke down the problem by adding 6i + 15i= 21i=x+6i, then i made the 21i negative on both sides:
21i = x + 6i
-21i -21i= -15, is this correct?
Answer by ayman11(2) (Show Source):
You can put this solution on YOUR website! 3i(2+5i) = x + 6i
3i .2 + 3i . 5i = x + 6i
6i + 15 (i)^2 = x + 6 i
6 i - 15 = x + 6i by adding ( - 6 i ) to both sides
- 6 i -6i
-15 = x
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