SOLUTION: Please help me solve these problems.
Factor. Check by multiplying
4x^5 y^3+16x^3 y^2+32xy and
9x^2=72x and
factor by grouping
21x^3-15x^2+28x-20.
Thank you very much!
Algebra.Com
Question 140851: Please help me solve these problems.
Factor. Check by multiplying
4x^5 y^3+16x^3 y^2+32xy and
9x^2=72x and
factor by grouping
21x^3-15x^2+28x-20.
Thank you very much!
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
# 1
Start with the given expression
Factor out the GCF
Now let's focus on the inner expression
------------------------------------------------------------
Looking at we can see that the first term is and the last term is where the coefficients are 1 and 8 respectively.
Now multiply the first coefficient 1 and the last coefficient 8 to get 8. Now what two numbers multiply to 8 and add to the middle coefficient 4? Let's list all of the factors of 8:
Factors of 8:
1,2,4,8
-1,-2,-4,-8 ...List the negative factors as well. This will allow us to find all possible combinations
These factors pair up and multiply to 8
1*8
2*4
(-1)*(-8)
(-2)*(-4)
note: remember two negative numbers multiplied together make a positive number
Now which of these pairs add to 4? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 4
First Number | Second Number | Sum | 1 | 8 | 1+8=9 |
2 | 4 | 2+4=6 |
-1 | -8 | -1+(-8)=-9 |
-2 | -4 | -2+(-4)=-6 |
None of these pairs of factors add to 4. So the expression cannot be factored
------------------------------------------------------------
Answer:
So factors to
# 2
Start with the given equation
Subtract 72x from both sides.
Factor out the GCF 9x
Now set each factor equal to zero:
or
or Now solve for x in each case
So our answers are
or
# 3
Start with the given expression
Group like terms
Factor out the GCF out of the first group. Factor out the GCF out of the second group
Since we have the common term , we can combine like terms
So factors to
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