SOLUTION: (3+3i/1-i)^2
Algebra.Com
Question 138737: (3+3i/1-i)^2
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
[(3+3i) / (1-i)]^2
Multiply numerator and denominator by 1+i to get:
= [(3(1+i)^2 / (1+1)]^2
= [(3/2)(1+i)^2]^2
= [(9/4)(1+i)^4]
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Cheers,
Stan H.
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