SOLUTION: 1. (3+2i)squared(3-2i)squared (3+2i)(3+2i)(3-2i)(3-2i) 9+6i+6i+4isquared 9-6i-6i+4isquared 9+12i+4(-1) 9-12i+4(-1) (5+12i)(5-12i)

Question 133210: 1. (3+2i)squared(3-2i)squared
(3+2i)(3+2i)(3-2i)(3-2i)
9+6i+6i+4isquared 9-6i-6i+4isquared
9+12i+4(-1) 9-12i+4(-1)
(5+12i)(5-12i)
=169

Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
You are absolutely correct. There was, however, a slightly more elegant and certainly simpler way to do this one.

First, re-arrange the factors:

Now you have two sets of conjugates to multiply:
, so:

Like my Daddy always used to say, "There's more'n one way to skin a cat." Keep an eye out for these sorts of things. They will save you lots of time and frustration, particularly at test time.
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