SOLUTION: 1-i/1+i*2+i/1+i
Algebra.Com
Question 132965This question is from textbook
: 1-i/1+i*2+i/1+i
This question is from textbook
Found 2 solutions by vleith, jim_thompson5910:
Answer by vleith(2983) (Show Source): You can put this solution on YOUR website!
i/1 = i
-i/i = -i
Thus we get
Yielding
Collecting like term yields
If, by chance you meant to write instead of then just do the same steps but substitute -1 for
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given expression
Combine the fractions
Foil the numerator
Combine like terms
Replace with -1
Combine like terms
Foil the denominator
Combine like terms
Replace with -1
Combine like terms
Multiply the fraction by
Multiply the fractions
and to get
Replace with -1
Multiply
Distribute
Replace with -1
Multiply
Rearrange the terms
Break up the fraction
Reduce
----------------------------------------------------
Answer:
So simplifies to
In other words,
RELATED QUESTIONS
{{{((1+i)/(1-i))^2 + 1/(x+iy) =... (answered by Edwin McCravy)
{-1, 2- i, 2+... (answered by ikleyn)
Simplify: 1 + i/2 -... (answered by Fombitz)
Simplify : (1+i)^2+(1-i)^2
(answered by Alan3354)
2+i/(3+i)(1+i)
(answered by Alan3354)
(5i)/((1-i)(2-i)(3-i))
(answered by MathLover1)
Compute (1 + i) + (2 - i) + (3 +... (answered by mccravyedwin)
(1-i)(1-i)(1-i) (answered by MathLover1)
(1/2-i)^2 (answered by Mathtut)