SOLUTION: From a point 𝐿 outside a circle, we drew tangents to the circle at points 𝐴 and B. From the same point L, we also drew a secant to the circle passing through points g and D,

Question 1209128: From a point 𝐿 outside a circle, we drew tangents to the circle at points 𝐴 and B. From the same point L, we also drew a secant to the circle passing through points g and D, where point g lies between L and D. We selected apoint k on the chord BD such that the measure of the angle ∠(𝑘𝐴𝐷) = ∠(𝐿𝐵g)
Find the following ratio:Measure of ∠(𝐾𝐵𝐷):Measure of ∠(𝐿𝐴𝑔)
Answer by greenestamps(13198) (Show Source): You can put this solution on YOUR website!

The problem is very probably stated incorrectly.

(Or, if it is stated correctly, then it is a joke.)

If point K is on chord BD, then angle KBD is zero, so the ratio of the measure of angle KBD to the measure of any other angle is zero.

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