SOLUTION: if dy/dx = sec(x) , dt/dx = tan(x) - 3, then ,(d ^2 y)/(dt ^2) =... when(x = 0
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Question 1208214
:
if dy/dx = sec(x) , dt/dx = tan(x) - 3, then ,(d ^2 y)/(dt ^2) =... when(x = 0
Answer by
mccravyedwin(406)
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Substitute x = 0 sec(0) = 1, tan(0) = 0
, substitute x=0, get -3, So
when x=0
Edwin
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