SOLUTION: 0 , 1 , 1 , 3 , 10 , 103 , x, y Find x , y

Question 1207332: 0 , 1 , 1 , 3 , 10 , 103 , x, y
Find x , y
Found 3 solutions by ikleyn, greenestamps, math_tutor2020:
Answer by ikleyn(52788)   (Show Source): You can put this solution on YOUR website!
.

Makes no sense.

Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!

Presumably this is a question where we are supposed to determine the next two numbers in the sequence.

In that case, it is not a math question at all; it is merely a guessing game. Any two next numbers will make a valid sequence. In fact, x and y don't even have to be numbers; you can put ANYTHING for x and y and have a valid sequence. So, for example, the sequence as given -- "0 , 1 , 1 , 3 , 10 , 103 , x, y" -- is as good an answer as any.

If this is supposed to be a math problem, with two numbers for x and y, then the only way to find THE answer is to ask the author of the problem what the answer is.

Answer by math_tutor2020(3817)   (Show Source): You can put this solution on YOUR website!

Sequence problems like this are fundamentally flawed.

Why is that?
Check out my previous response on this page for more information.
https://www.algebra.com/algebra/homework/Sequences-and-series/Sequences-and-series.faq.question.1195799.html
The summary of what I mention is that the sequence 1,2,4 could have infinitely many possible numbers as the fourth term; questions that ask about the next term are often too vague to answer. Further context is needed.

RELATED QUESTIONS
Simplify the following exponential expression: x-2/y-4 and Perform the following... (answered by ikleyn,greenestamps,Alan3354)
y=1/3x +10/3 find x and... (answered by Fombitz)
(1/x)-(3/y)=-8/3 (4/x)+(2/y)=-10/3 find x, & y. (answered by Alan3354)
y=3-2y x=0... (answered by Alan3354)
y = 1/2x^2 -2 x y 0 ? 1 ? 2 ? 3 ? Find... (answered by checkley77,jojo14344)
y=x+2 find the value of y x y 0 1 2 3... (answered by richard1234)
Find the solution to the equations. 2x - y = -3 x + y = 0 (0, 0) (-1, 1) (1,... (answered by math_helper)
1/x + 2/y - 4/z = 1 2/x + 3/y + 8/z = 0 -1/x + 9/y + 10/z = 5 then solve x, y and... (answered by Fombitz)
(x/3) + (y/6) = 1 (x/4) - (y/8) =... (answered by stanbon)