SOLUTION: what are the last two digits of the number {{{ 7^8910 }}} when it is fully calculated out?
Algebra.Com
Question 1191159: what are the last two digits of the number when it is fully calculated out?
Answer by greenestamps(13209) (Show Source): You can put this solution on YOUR website!
The sequence of the last two digits of increasing powers of 7 will form a repeating pattern. Use the length of that pattern to find the answer.
07
49
43
01
07
....
That is a very short pattern with length 4.
The exponent 8910, divided by 4, leaves remainder 2, so the answer is the 2nd number in the repeating pattern: 49
ANSWER: 49
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