.
We are given that = 2.
It implies | x + i(y+2) | = 2 * |(x+1) + iy |.
In turn, it means that
x^2 + (y+2)^2 = 4 * ((x+1)^2 + y^2).
Simplify it a bit
x^2 + y^2 + 4y + 4 = 4*(x^2 + 2x + 1 + y^2),
x^2 + 4y + y^2 + 4 = 4x^2 + 8x + 4 + 4y^2,
3x^2 + 8x + 3y^2 - 4y = 0.
Complete the squares separately for x-terms and y-terms
+ =
+ =
+ = .
It is EXACTLY the answer given in your post.
By the way, it is an equation of the circle of the radius of = centered at the point (,).
So, the locus of { w } is the described circle. ANSWER
Solved, answered, explained and completed.