SOLUTION: Solve for x: x^2= 3x-5

Question 1170613: Solve for x: x^2= 3x-5
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
the equation is x^2 = 3x - 5

subtrct 3x from both sides of the equation and add 5 to both sides of the equation to get:

x^2 - 3x + 5 = 0.

use the quadratic equation to solve this quadratic equation to get:

the roots are:

z = 1.5 + 1.6583123951777i or x = 1.5 - 1.6583123951777i

those are the roots of the equation, which are complex numbers that contain an imaginary part because the equation does not cross the line y = 0.

if the roots were real, the graph of the equation would have cross the x-axis.

the x-axis is when the value of y on the graph is equal to 0.

the quadratic equation solves for the roots, even if they are not real.

a complex number has a real part and an imaginary part.

the real part is a real number.

the imaginary part is a real number times the letter i.

the letter i represents the square root of (-1).

here's a reference on complex numbers.

https://www.mathsisfun.com/numbers/complex-numbers.html

there are many more references on the web.
just do a search for complex numbers.

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