SOLUTION: Solve for x: x^2+16=0 (complex numbers)
Algebra.Com
Question 1170561: Solve for x: x^2+16=0 (complex numbers)
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
equation is x^2 + 16 = 0
subtract 16 from both sides of the equqtion to get:
x^2 = -16
solve for x to get:|
x = plus or minus sqrt(-16)
sqrt(-16) = sqrt(16*-1) = 4*sqrt(-1) = = 4i
x = plus or minus 4i.
that should be your answer.
to confirm, replace x with plus or minus 4i in the original equation to get:
when x = 4i,the equation becomes (4i)^2 + 16 = 0.
(4i)^2 becomes 4^2 * i^2 = 16 * -1 = -16.
equation becomes -16 + 16 = 0, which is true, confirming x = 4i is a solution.
when x = -4i, the equation becomes (-4i)^2 + 16 = 0
(-4i)^2 becomes (-1)^2 * 4^2 * i^2 = 1 * 16 * -1 = -16.
equation becomes -16 + 16 = 0, which is true, confirming x = -4i is also a solution.
the solution is x = plus or minus 4i.
RELATED QUESTIONS
how would i solve equations over complex numbers? for example,... (answered by jim_thompson5910)
Solve 2(x-1)^2 = -16 over the set of complex... (answered by Nate)
Solve the equation over complex numbers
x^2 – 16 =... (answered by richwmiller)
Solve x^3 - x^2 - 7x +15 =0 over the set of complex... (answered by solver91311)
Solve giving real and complex numbers:
x^3 - 3x^2 + x - 3 =... (answered by KMST)
Solve x^3 - 4x^2 - 2x + 20 = 0 over the set of complex... (answered by Nate)
solve equation using imaginary and complex numbers x^2+4x+24=0
please help!... (answered by jim_thompson5910)
Solve for x: x^2 + 7x + 4 = 0. If the solutions are complex numbers, then give your... (answered by josmiceli)
-3i-x+(2i)^4=3+2i/2-i
x=all complex numbers
Solve for x
Thank You in... (answered by stanbon)