SOLUTION: Given |z1|=|z2| show that arg(z1+z2) = {{{arg((z1+z2)^2)}}}. I don't how how to use |z1| = |z2|. Without that, I can work out that argz1 + argz2 = 2arg(z1+z2), but they don't

Question 1167491: Given |z1|=|z2| show that arg(z1+z2) = .
I don't how how to use |z1| = |z2|. Without that, I can work out that
argz1 + argz2 = 2arg(z1+z2), but they don't equal one another.
Answer by ikleyn(52814)   (Show Source): You can put this solution on YOUR website!
.

            This statement is   INCORRECT.

Counter-example: consider    = 1,    = i.

Then   arg () = ;     arg () =   and the equality fails.

Please do not post FAKE problems to this forum.

By doing so, you steal the tutor's time and my time, in particular.

At this spot, another post from other student could be placed, who really needs my help and attention.

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