SOLUTION: (x-3)^2 +(y-2)^2=16 find the equation of the tangent line at the point (-2,1)
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Question 1159059: (x-3)^2 +(y-2)^2=16 find the equation of the tangent line at the point (-2,1)
Found 2 solutions by greenestamps, MathLover1:
Answer by greenestamps(13203) (Show Source): You can put this solution on YOUR website!
The given point is not on the given curve....
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
The given point (,) is not on the given curve.
check:
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