SOLUTION: A solution for z^3 + 2 + 2root3i = 0
1) 2^2/3(cos4pi/9 + i.sin 4pi/9)
2) 4^1/4(cos11pi/12 + i.sin11pi/12)
3) 2^2/3(cos 17pi/12 + i.sin17pi/12)
4) 4^1/3(cos7pi/6 + i.
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Question 1157653: A solution for z^3 + 2 + 2root3i = 0
1) 2^2/3(cos4pi/9 + i.sin 4pi/9)
2) 4^1/4(cos11pi/12 + i.sin11pi/12)
3) 2^2/3(cos 17pi/12 + i.sin17pi/12)
4) 4^1/3(cos7pi/6 + i.sin7pi/6)
5) 2^2/3(cos11pi/12 + i.sin 11pi/12)
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
Use deMoivre's Theorem.
That is equivalent to answer 1.
ANSWER: 1) 2^2/3(cos4pi/9 + i.sin 4pi/9
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