SOLUTION: 2t+t+5=3 Subtract 3 on both sides 2t+t-2=0 AC=4 B=1 Possibilities for products of 4 are (1 and 4), (2 and 2) I can't find a product of 4 that equals the sum of 1 and this

Question 1151634: 2t+t+5=3
Subtract 3 on both sides
2t+t-2=0
AC=4
B=1
Possibilities for products of 4 are (1 and 4), (2 and 2)
I can't find a product of 4 that equals the sum of 1 and this is where I get stuck. I tried to use the quadratic formula, but that did not work out so well. What problems would I use the quadratic formula for?
How do you solve problems like the one above where their is no product of ac that equals the sum of b?
Thank you for your help
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
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2t+t+5=3
Subtract 3 on both sides
2t+t-2=0
---------------------------------------------

The rest of your description is unrelated to the first part of it.

----------

?

Does not appear factorable, so....

Your AC and B do not seem to fit anything here.
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!

2t+t+5=3
Subtract 3 on both sides
2t+t-2=0
AC=4
B=1
Possibilities for products of 4 are (1 and 4), (2 and 2)
I can't find a product of 4 that equals the sum of 1 and this is where I get stuck. I tried to use the quadratic formula, but that did not work out so well. What problems would I use the quadratic formula for?
How do you solve problems like the one above where their is no product of ac that equals the sum of b?
Thank you for your help

There are NO INTEGERS with a product of 4 that sum to 1. You seem to be referring to a quadratic equation the likes of: x² + x + 4 = 0.
The quadratic equation formula or COMPLETING the SQUARE would need to be used to find the roots.
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