SOLUTION: I need help solving this problem: So far I have this:
x/x2+5x+6 - 2/x2+3x+2
x/(x+2)(x+3) - 2/(x+2)(x+1) but I don't know what to do next.
Algebra.Com
Question 1151158: I need help solving this problem: So far I have this:
x/x2+5x+6 - 2/x2+3x+2
x/(x+2)(x+3) - 2/(x+2)(x+1) but I don't know what to do next.
Found 2 solutions by MathLover1, jim_thompson5910:
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!
........common denominator for and is
....simplify
...for
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Great job so far getting the proper factorizations.
Examine the denominators
(x+2)(x+3) and (x+2)(x+1)
We have the unique factors: (x+2), (x+3) and (x+1)
These unique factors form the Lowest Common Denominator (LCD).
The LCD is (x+1)(x+2)(x+3).
The goal is to get each fraction to have the LCD. For the first fraction we have (x+2)(x+3). What's missing to have this turn into the LCD? That would be (x+1).
So we must multiply top and bottom of the first fraction by (x+1) so we get to the LCD.
The first fraction turns into after performing this step.
-------------------------------------------
Now turn to the second fraction
which is the same as
What's missing from the denominator to have it equal to the LCD? That would be (x+3).
Multiply top and bottom of this fraction by (x+3) to get...
So turns into
-------------------------------------------
To summarize so far:
turns into
turns into
From here, we can subtract the fractions as the denominators are both the same.
Your answer would either be or depending on if your teacher wants you keep the denominator factored or not.
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