Using DeMoivre's theorem:Using the binomial theorem: Then we use i2 = -1 i3 = -i i4 = 1 i5 = i i6 = -1 i7 = -i We can equate the two expressions for cos(7q) + i∙sin(7q) We equate the REAL parts on each side: We equate the IMAGINARY parts on both sides: Dividing through by i: So we have identities for both cos(7q) and sin(7q) You do the other one the same way. I'll help you with the binomial theorem part: Edwin