SOLUTION: How long would a day be on Earth if instead of spinning at its usual 1000 mph the Earth rotated at 28,000 mph like the fastest-spinning planet Jupiter? They have an answer of 52

Question 1141642: How long would a day be on Earth if instead of spinning at its usual 1000 mph the Earth rotated at 28,000 mph like the fastest-spinning planet Jupiter?
They have an answer of 52 minutes but don't know how they got the answer.
How would you go about solving? Thanks in advance.
Found 2 solutions by GareBare, Alan3354:
Answer by GareBare(1) (Show Source): You can put this solution on YOUR website!
Given that a day is about 86400 seconds, you should just divide that by 28 because you are having it be 28 times faster. That should get you an awnser of 3085.7 and then divide that by 60 (because 60 seconds in a minute) and that should give you about 51.4 for your answer which would be in minutes and you can round up to 52 minutes. Hope this helps!
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
How long would a day be on Earth if instead of spinning at its usual 1000 mph the Earth rotated at 28,000 mph like the fastest-spinning planet Jupiter?
They have an answer of 52 minutes but don't know how they got the answer.
How would you go about solving?
---------------
Spinning 28 times as fast, not "28 times faster," it takes 1/28 as long to rotate once on its axis/
---> 1/28 of a day --> 1440/28 minutes
==================
PS The Earth's speed of ~1000 mi/hr is only at the equator. At the poles, it's zero.

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