SOLUTION: find the root of equation for X^3=8=0 trying ans f(1)=9 f(-2)=0 so, x=-2 is the root x+2 is factor of f(x) (x+2)^3=0

Question 1141576: find the root of equation for X^3=8=0
trying ans
f(1)=9
f(-2)=0
so, x=-2 is the root
x+2 is factor of f(x)
(x+2)^3=0
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
find the root of equation for X^3=8=0
====================
Too many equal signs.
-------------
From your attempts, I can see that you meant
---
x^3 + 8 = 0
Factor it.
---
(x+2)*(x^2 - 2x + 4) = 0
---
x = -2
---------
(x^2 - 2x + 4) = 0

Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

The discriminant -12 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.

In the field of imaginary numbers, the square root of -12 is + or - .

The solution is , or
Here's your graph:

---> roots are -2 and
1 + i*sqrt(3) and
1 - i*sqrt(3)
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