SOLUTION: how would you work 3 - i over 2 - i
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Question 113127
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how would you work 3 - i over 2 - i
Answer by
stanbon(75887)
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how would you work 3 - i over 2 - i
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Multiply numerator and denominator by 2+i to get:
[(3-i)(2+i)]/[2^2-i^2]
= [6+i+1]/5
= [7+i]/5
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Cheers,
Stan H.