SOLUTION: how would you work 3 - i over 2 - i
Algebra.Com
Question 113127: how would you work 3 - i over 2 - i
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
how would you work 3 - i over 2 - i
---------------
Multiply numerator and denominator by 2+i to get:
[(3-i)(2+i)]/[2^2-i^2]
= [6+i+1]/5
= [7+i]/5
=========
Cheers,
Stan H.
RELATED QUESTIONS
I know I am making this harder than it is! Would you please help me with how to work this (answered by edjones)
how would i graph
y = 3 over 4 x + 2 (answered by checkley71)
How would I solve this rational equation
x+6 over 3x-12
=
5 over x-4
+
2 over 3
(answered by josgarithmetic)
How would I work the following problem? I need to rationalize the denominator of this... (answered by Fombitz)
How would you solve the problem i^7+i^2+i^12+i^9 over... (answered by Earlsdon,josmiceli)
How would you work this problem 2x+1 over 8 epuals 3 over... (answered by tutor_paul)
I forgot how to work out this equation, 2+1/4 over... (answered by solver91311)
I was wondering how you would work out 1/3 - 2/11 because 3 doesn't go into 11. I am very (answered by Edwin McCravy)
Hello I was doing my homework on quadratic functions and I have a question on a problem... (answered by nerdybill)