SOLUTION: help! how would you work out 2- 4i over 1+ 3i

Algebra.Com
Question 113126: help!
how would you work out 2- 4i over 1+ 3i

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
2- 4i over 1+ 3i
---------------------
Multiply numerator and denominator by 1-3i to get:
[(2-4i)(1-3i)]/[1^2-(3i)^2]
= [2-10i-12]/[10]
= [-10-10i]/10
= -1-i
=========
Cheers,
Stan H.

RELATED QUESTIONS

2+3i/1+4i (answered by stanbon)
(1+4i)-(-2+3i) (answered by Alan3354,ikleyn)
Please help with this. How do I add complex numbers? 1. (3+2i)+(4-4i) 2. (1+4i)+... (answered by solver91311)
(2+3i)/(-4i)+(2+4i)/(1+i) (answered by CharlesG2)
simplify... (answered by AnlytcPhil)
Can you help my son work out... (answered by Alan3354)
How do you do this problem with work on how you did it? Add these complex numbers. Write (answered by jim_thompson5910,Simnepi)
how do you solve... (answered by Alan3354)
how do you simplify... (answered by Fombitz)