SOLUTION: I have a problem I'm not sure I solved right -4+1i/3i What I did was (-4+1i/3i)(i/i) = -4+1/3 = -3/3 = -1 Is this correct?

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Question 1112640: I have a problem I'm not sure I solved right
-4+1i/3i
What I did was (-4+1i/3i)(i/i) = -4+1/3 = -3/3 = -1
Is this correct?
Found 3 solutions by stanbon, josgarithmetic, MathTherapy:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
I have a problem I'm not sure I solved right
-4+1i/3i
-----
The conjugate of 3i is -3i
------
Multiply numerator and denominator by that conjugate to get:
[-3i(-4+i)]/[-3i(3i)]
----
= (3+12i)/9
-----
= (1+4i)/3
----------------------
Cheers,
Stan H.
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Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
I assume you really start with this, , because the apparent term in your posting showing would be a poor way to show part of the original expression.







You know what to do from here. (Know that .)
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

I have a problem I'm not sure I solved right
-4+1i/3i
What I did was (-4+1i/3i)(i/i) = -4+1/3 = -3/3 = -1
Is this correct?
(-4 + 1i/3i)(i/i) <====== This is correct, but nothing else

The above in a more legible form:  

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