SOLUTION: A two digit number whose ten digit is 2 more than the units digit is 3 more than 6 times the sum of its digits. Find the original number

Question 1106095: A two digit number whose ten digit is 2 more than the units digit is 3 more than 6 times the sum of its digits. Find the original number
Found 2 solutions by greenestamps, josgarithmetic:
Answer by greenestamps(13198) (Show Source): You can put this solution on YOUR website!

(1) Let the units digit be x; then the tens digit is x+2.

(2) The value of the number is 10(x+2)+x = 11x+20.

(3) 3 more than 6 times the sum of the digits is 6((x+2)+x)+3 = 12x+15.

The problem tells us that the expressions in (2) and (3) are equal:

The units digit is 5; the tens digit is 7.

CHECK: 6(5+7)+3 = 75
Answer by josgarithmetic(39616) (Show Source): You can put this solution on YOUR website!
t, tens digit
u, units digit

-

The number is 75.
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