SOLUTION: Find the values of k, for which the equation kx^2+6x+k=0, has conjugate imaginary roots.

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Question 1104919: Find the values of k, for which the equation kx^2+6x+k=0, has conjugate imaginary roots.
Answer by greenestamps(13200) About Me  (Show Source):
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The equation has conjugate complex (not pure imaginary) roots whenever the discriminant is negative.

b%5E2-4ac+=+6%5E2-4%28k%29%28k%29+=+36-4k%5E2

The discriminant is negative whenever |k|>3.

The given equation has conjugate complex roots when x is less than -3 or greater than 3.