SOLUTION: z = a + bi ---- a complex number. sin(z) = 2 Solve for z.

SOLUTION: z = a + bi ---- a complex number. sin(z) = 2 Solve for z.

Algebra.Com

Question 1104804: z = a + bi ---- a complex number.
sin(z) = 2
Solve for z.

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
z = a + bi ---- a complex number.
sin(z) = 2
Solve for z.
===================
This is quite tedious.
Look at http://www.suitcaseofdreams.net/Sine_Complex.htm
---
-->
k = integer

RELATED QUESTIONS
For the complex number a + bi, what is z bar (z with a line over... (answered by Alan3354)

Let z = a + bi represent a general complex number. As noted in the lesson, the conjugate... (answered by jim_thompson5910)

COMPLEX NUMBER If {{{z = a+bi}}} and {{{abs((z-i)/(z+2+i))=3}}}, show that {{{8a^2 +... (answered by Edwin McCravy)

If z is a complex number satisfying z + \frac{1}{z} = \sqrt{2}, calculate z^{10} (answered by CPhill)

If z is a complex number, solve the equation... (answered by josgarithmetic)

y=z/z-a solve for... (answered by macston)

I am having trouble with these two questions. Can someone please explain. 1. Let z = a (answered by oscargut)

18. Let z = a + bi represent a general complex number. As noted in the lesson, the... (answered by solver91311)

Solve: |z| + z = 2 + i , where z is a complex... (answered by ikleyn)