SOLUTION: how do you find the multiplicative inverse of 3-i

Question 1102140: how do you find the multiplicative inverse of 3-i
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
how do you find the multiplicative inverse of 3-i
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Solve (3-i)x = 1 for 'x
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x = 1/(3-i)
Multiply numerator and denominator by 3+i to get:
x = (3+i)/[(3-i)(3+i)]
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x = (3+i)/[9-i^2] = (3+i)/[9+1] = (3/10)+ (1/10)i
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Cheers,
Stan H.
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