SOLUTION: solve the following equation for real numbers x and y. ((1+i)/(1-i))^2+1/(x+iy)=1+i.

SOLUTION: solve the following equation for real numbers x and y. ((1+i)/(1-i))^2+1/(x+iy)=1+i.

Algebra.Com

Question 1095684: solve the following equation for real numbers x and y.
((1+i)/(1-i))^2+1/(x+iy)=1+i.

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
solve the following equation for real numbers x and y.

----------------

-->

Invert

x = 2/5, y = -1/5
RELATED QUESTIONS
solve the following equation for real numbers x and y.... (answered by ikleyn)

{{{((1+i)/(1-i))^2 + 1/(x+iy) =... (answered by Edwin McCravy)

EXPRESS 1+i/1-i in the form... (answered by Fombitz)

Solve for x and y, 3x + iy = (1 + i)(x^2 + y^2). Ans: x = 3/10 and y =... (answered by math_helper)

1/z = 1/(2 + i) + 1/(-2 + 4i), evaluate z in the form x +... (answered by math_helper)

find the Cartesian form of x+iy of the complex numbers... (answered by ikleyn,greenestamps)

(2+i)(1+2i)/3+4i express in the form of... (answered by Alan3354)

i am having trouble solving: find real numbers x and y if: (x+i)(3-iy)= 1+13i i have... (answered by tommyt3rd)

Please help me solve the following problem Find all the values of z such that... (answered by math_helper)