SOLUTION: A basketball team sells tickets that cost $10, $20, and VIP seats for $30. The team has sold 3408 tickets overall. It has sold 129 more $20 tickets than $10 tickets. The total s

Question 1077455: A basketball team sells tickets that cost $10, $20, and VIP seats for $30. The team has sold 3408 tickets overall. It has sold 129 more $20 tickets than $10 tickets. The total sales are $64,460. How many $10 tickets, $20 tickets, and $30 tickets have been sold?

Answer by ikleyn(52788) (Show Source): You can put this solution on YOUR website!
.

Let x be the number of $10 tickets, and let y be the number of $30 tickets.

Then the number of $20 tickets is (x+129).

The system of two equations in two unknowns is

x + (x+129) + y = 3408.         (1)    (The total number of tickets)
10x + 20(x+129) + 30y = 64460   (2)   (The total sales)


Simplify and solve.

The lesson to learn from his solution:

     This problem reduces to two unknowns.
     It is not about 3 unknowns.

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