SOLUTION: Find a number that is 68 greater than three times its opposite

SOLUTION: Find a number that is 68 greater than three times its opposite

Algebra.Com

Question 106939This question is from textbook Structure and Method
: Find a number that is 68 greater than three times its opposite This question is from textbook Structure and Method

Answer by cheesey(22) (Show Source): You can put this solution on YOUR website!
x = 3(-x) + 68
x = -3x + 68
3x + x = -3x + 3x + 68
4x = 68
x = 17

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