SOLUTION: A block of ice at 0 degrees C, whose mass is initially 50.0 kg, slides along a horizontal surface, starting at a speed of 5.84 m/s and finally coming to rest after traveling 21.8 m

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Question 1066975: A block of ice at 0 degrees C, whose mass is initially 50.0 kg, slides along a horizontal surface, starting at a speed of 5.84 m/s and finally coming to rest after traveling 21.8 m. Compute the mass of ice melted (in grams) as a result of friction between the ice and the horizontal surface.
Answer by ikleyn(52755) About Me  (Show Source):
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A block of ice at 0 degrees C, whose mass is initially 50.0 kg, slides along a horizontal surface,
starting at a speed of 5.84 m/s and finally coming to rest after traveling 21.8 m. Compute the mass of ice melted (in grams)
as a result of friction between the ice and the horizontal surface.
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The amount of energy that was spent for the ice melting was exactly equal to the initial kinetic energy of the block of ice

E = %28m%2Av%5E2%29%2F2 = %2850%2A5.84%5E2%29%2F2 = 852.64 Joules.


Ice melting lateral heat is  334 kJ/kg = 334000 J/kg.

    (see http://www.engineeringtoolbox.com/latent-heat-melting-solids-d_96.html


Therefore, the melted mass of the ice is  852.64%2F334000 = 0.00255 kg = 2.55 g.