SOLUTION: If {{{1/(a+u)+1/(b+u)+1/(c+u)+1/(d+u)=2/u}}},
{{{1/(a+v)+1/(b+v)+1/(c+v)+1/(d+v)=2/v}}},
Where u and v are imaginary cube roots of unity and a, b, c, d are constants,
then prove
Algebra.Com
Question 1062528: If ,
,
Where u and v are imaginary cube roots of unity and a, b, c, d are constants,
then prove that
,
Answer by ikleyn(52802) (Show Source): You can put this solution on YOUR website!
.
The competent mathematician will never write
". . . imaginary cube roots of unity",
because they are not imaginary. They are COMPLEX instead.
What is the source of this problem ?
I just saw this problem once (long time ago) in this forum and worked on it.
And my conclusion was: the formulation is wrong/incorrect.
So, my question is: WHAT IS THE SOURCE OF IT ?
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