SOLUTION: A pellet gun fires ten 3.00 g pellets per second with a speed of 530 m/s. The pellets are stopped by a rigid wall. What is the average force (in newtons) exerted by the pellets on

Question 1057838: A pellet gun fires ten 3.00 g pellets per second with a speed of 530 m/s. The pellets are stopped by a rigid wall. What is the average force (in newtons) exerted by the pellets on the wall?
Answer by ikleyn(52834) (Show Source): You can put this solution on YOUR website!
.

It is about and around this equation 

Ft = mV     (or  Ft = n*(mV) "= 10*(mV)" )

("the impulse of the force is equal to the change of the momentum").

The momentum change is n*(m*V) = 10*(3*530) g*m/s.

The time is 1 second.

Therefore, the averaged force is  =  =  = calculate.



But still keep in mind that the "real" force of one/each separate strike can be significantly different from the averaged force.

Because the interaction time can be significantly shorter than  of a second.

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