SOLUTION: A block of mass 4.62 kg is drawn at constant speed a distance of 1.78 m along a horizontal floor by a rope exerting a constant force of magnitude 1.24 N and making an angle of 11.0

Question 1056853: A block of mass 4.62 kg is drawn at constant speed a distance of 1.78 m along a horizontal floor by a rope exerting a constant force of magnitude 1.24 N and making an angle of 11.0 degrees above the horizontal. Compute the coefficient of friction between the block and the floor.

Answer by ikleyn(52814) (Show Source): You can put this solution on YOUR website!
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A block of mass 4.62 kg is drawn at constant speed a distance of 1.78 m along a horizontal floor by a rope exerting a constant force
of magnitude 1.24 N and making an angle of 11.0 degrees above the horizontal.
Compute the coefficient of friction between the block and the floor.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Decompose the given force F into the horizontal and vertical components.
The horizontal component is equal to |F|*cos(11�), the vertical component is |F|*sin(11�).
The reaction force N acts from the floor vertically up to the box. Together with
the vertical component Fy it balances the weight: |W| = + |N|. So, |N| = |W| - .

The friction coefficient is the ratio of the shear force to the reaction force |N|:

= = = .

Complete these calculations. Surely, W = mg = 4.62*9.81 Newtons.

Figure. The body on the horizontal floor

Similar problem was solved in my lesson
- Using vectors to solve problems in Mechanics: Force
in this site.

I simply copied and pasted the solution (the text and the Figure) from there and replaced the input data.

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