SOLUTION: z^2=5-12i Where z=a+bi How to do it, help ls

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Question 1046823: z^2=5-12i
Where z=a+bi
How to do it, help ls

Found 3 solutions by Alan3354, ankor@dixie-net.com, ikleyn:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Do what?
Answer by ankor@dixie-net.com(22740)   (Show Source): You can put this solution on YOUR website!
z^2=5-12i
Where z=a+bi
:
Replace z with (a+bi)
(a+bi)^2 = 5 - 12i
:
FOIL (a+bi)(a+bi)
a^2 + 2abi + b^2i^2 = 5 -12i
:
i^2 = -1 therefore
a^2 + 2abi - b^2 = 5 - 12i
a^2 + 2abi = b^2 + 5 - 12i
a^2 + 2abi + 12i = b^2 + 5
:
I don't know what else you can do with it.

Answer by ikleyn(52908)   (Show Source): You can put this solution on YOUR website!
.
z^2=5-12i
Where z=a+bi
How to do it, help ls
~~~~~~~~~~~~~~~~~~~~

z = a + bi   --->   =  =  =     (since  =  =  =    //  <--- since  = -1)

Now you have, from the condition, an equality of these two complex numbers:

 = 5 - 12i.

It means that the real parts are equal and the imaginary parts are equal:

 = 5,     (1)
2ab = -12.       (2)


It is the system of two equations for the two unknowns "a" and "b".
To solve it, express b =  =  from (2) and substitute it into (1). You will get

 = 5,    or

 -  = 5.

Multiply both sides by a^2. You will get

 = 0.

Factor the left side

 = 0.


The equation deploys in two independent equations


1.   = 0  --->   = 9  --->  a = +/- 3  --->  b = -6/a = -/+ 2.


2.   = 0  --->   = -4  --->  No real solutions.


Answer. The solutions of the original equation  = 5 - 12i are these two complex numbers:  = 3 - 2i  or/and   = -3 + 2i.

       In other words, the square root of the complex number 5 - 12i in the complex domain are these two complex numbers: 3 - 2i  and  -3 + 2i.

There is a bunch of my lessons on complex numbers
    - Complex numbers and arithmetical operations on them
    - Complex plane
    - Addition and subtraction of complex numbers in complex plane
    - Multiplication and division of complex numbers in complex plane
    - Raising a complex number to an integer power
    - How to take a root of a complex number
    - Solution of the quadratic equation with real coefficients on complex domain
    - How to take a square root of a complex number
    - Solution of the quadratic equation with complex coefficients on complex domain
in this site.


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