SOLUTION: Simplify 3+5i/2i
Algebra.Com
Question 1038209: Simplify 3+5i/2i
Found 2 solutions by Othel, josgarithmetic:
Answer by Othel(27) (Show Source): You can put this solution on YOUR website!
When dividing complex numbers, we multiply the numerator and denominator by something called the complex conjugate of the denominator. Long words for a simple idea. Basically, it is the negative of the complex number in the divisor. By doing this, we eliminate the complex number, and are left with a positive, real number denominator, where we started out with a complex number. So...
(3 + 5i)/2i * (-2i)/(-2i) = (10-6i)/4
Which reduces to
(5 - 3i)/2, or 5/2 - 3i/2
On the bottom, 2i * -2i = (-4)(i^2). Working with complex numbers, you must know that i^2 is -1. So this expression is equal to (-4)(-1). Which equals 4.
And on the top, (3)(-2i) = -6i, and (5i)(-2i) = (-10)(i^2) = (-10)(-1) = 10
Hope this helps! Learn on
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
3+5i/2i OR maybe....
RELATED QUESTIONS
simplify... (answered by jim_thompson5910)
Simplify:... (answered by Fombitz)
Simplify
3-2i-4i^3 /... (answered by robertb)
(5i-3)(2i-3)= (answered by drk)
-1 + 5i
________
3 +... (answered by rapaljer)
(3+2i)(4-5i) (answered by robertb)
3-5i/5+2i (answered by lynnlo,MathTherapy)
(3-2i)(6+5i) (answered by stanbon,Earlsdon,algebrahelp101)
Simplify (12+5i) -... (answered by solver91311,jim_thompson5910)