SOLUTION: The following equation has denominators that contain variables. for this equation write the value or values of the variable that make a denominator zero. these are the restrictions
Question 1031153: The following equation has denominators that contain variables. for this equation write the value or values of the variable that make a denominator zero. these are the restrictions on the variable. keeping the restrictions in mind, solve the equation.
2/11x + 1/4 = 81/22x - 1/3
My work for solving the equation is (2/11)x + 1/4 = (81/22)x - 1/3
24 x + 33 = 486 x - 44
77 = 462 x
x = 77/462
x = 7/42
x = 1/6 Found 2 solutions by josgarithmetic, MathTherapy:Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website! You very neatly indicated some groupings showing that the denominators contain no variables, so NO RESTRICTION on x is necessary. Did you really have something else?
You began with 2/11x + 1/4 = 81/22x - 1/3 and then you gave clarification of (2/11)x + 1/4 = (81/22)x - 1/3
and as rendered will look like .
You can put this solution on YOUR website! The following equation has denominators that contain variables. for this equation write the value or values of the variable that make a denominator zero. these are the restrictions on the variable. keeping the restrictions in mind, solve the equation.
2/11x + 1/4 = 81/22x - 1/3
My work for solving the equation is (2/11)x + 1/4 = (81/22)x - 1/3
24 x + 33 = 486 x - 44
77 = 462 x
x = 77/462
x = 7/42
x = 1/6
You're ALMOST correct. , not , with , as x = 0 makes the DENOMINATOR 0 (zero).
You have the equation backwards: Instead of 24x + 33 = 486x - 44. you should've had: 24 + 33x = 486 - 44x