SOLUTION: If {{{ 2−x^2 }}} ≤ {{{ g(x) }}} ≤ {{{ 2cos(x) }}} for all x, find lim(x→0) {{{ g(x) }}}
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Question 1013489: If ≤ ≤ for all x, find lim(x→0)
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Since cos(x) cannot be greater than 1, it appears that for
2 <= g(x) <= 2cos(x)
yields
1 <= (1/2)g(x) <= cos(x)
and cos(x) = (1/2)g(x) = 1
Now cos(0) = 1.
Therefore it appears g(0) = 2.
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