SOLUTION: Solve 4x^3+12x^2+12x+36

Algebra.Com
Question 1011015: Solve 4x^3+12x^2+12x+36
Found 2 solutions by Alan3354, fractalier:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Solve 4x^3+12x^2+12x+36
---
Not an equation.
Nothing to solve.

Answer by fractalier(6550)   (Show Source): You can put this solution on YOUR website!
If you meant
4x^3 + 12x^2 + 12x + 36 = 0
then we have
4(x^2 + 3)(x + 3) = 0
so that x = -3, +/- i*sqrt(3)

RELATED QUESTIONS

4x^3>12x^2 (answered by ewatrrr)
4x^3+8x^2-12x (answered by jim_thompson5910)
4x^3-12x^2+8x (answered by scott8148)
12x^3 +8x^2 +4x (answered by MathLover1)
x^2-12x+36 (answered by Alan3354)
x^2 + 12x... (answered by jim_thompson5910)
-12x/-2 = -36 (answered by josgarithmetic)
Solve each polynomial equation by factoring: 1. 4x^5 - 8x^3 + 4x = 0 2. x^4 - 12x^2 =... (answered by MathLover1)
Solve using the quadratic formula:... (answered by venugopalramana,atif.muhammad)