SOLUTION: The problem is .2 (x-5)=x+5. What I did below I'm not sure if it's correct. .2(x-5)=x +5 .2x-1=x+5 .2x=x+6 x=6

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: The problem is .2 (x-5)=x+5. What I did below I'm not sure if it's correct. .2(x-5)=x +5 .2x-1=x+5 .2x=x+6 x=6      Log On


   

Question 100897: The problem is .2 (x-5)=x+5. What I did below I'm not sure if it's correct.
.2(x-5)=x +5
.2x-1=x+5
.2x=x+6
x=6
Answer by diamonddarby2(3) About Me  (Show Source):
You can put this solution on YOUR website!
You did the first two steps right but when you got down to .2x-1=x%2B5 you should have subtracted the .2x from the 1x. Then you would have gotten -1=.8x%2B5. Next you would have subtracted 5 from both sides leaving you with -6=.8x Then you would have divided both sides by .8 Giving you and answer of x=-7.5
.2%28x-5%29=x%2B5
.2x-1=x%2B5
-1=.8x%2B5
-6=.8x
x=-7.5